在Python中强制复制一个小int [英] Force copy of a small int in Python
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问题描述
作为一个玩具问题,我试图提出对象 a,b
这样
As a toy problem, I tried to come up with objects a, b
such that
type(a) == type(b) == int # True
a + 1 == b + 1 == 1 # True
a is b # False
似乎 deepcopy
依赖于 _deepcopy_atomic
,如是否可以在Python中创建一个小int的副本?
Is it possible to create a copy of a small int in Python?
推荐答案
是的,这是可能的,并且没有低级的黑客或作弊行为:
Yes, it's possible, and without low level hacks or cheats:
>>> a = 0
>>> b = 9**99 % 9**99
>>> type(a) == type(b) == int
True
>>> a + 1 == b + 1 == 1
True
>>> a is b
False
我正在使用Python 3.8.1在本地进行此操作,但是您也可以在repl.it上复制它和 www.python.org/shell/.
I'm doing this locally with Python 3.8.1, but you can also reproduce it at repl.it and at www.python.org/shell/.
对于小的积极因素:
>>> a = 7
>>> b = (9**99 + a) % 9**99
>>> b, type(b), a == b, a is b
(7, <class 'int'>, True, False)
对于小底片:
>>> a = -2
>>> b = (9**99 + a) % -9**99
>>> b, type(b), a == b, a is b
(-2, <class 'int'>, True, False)
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