url中的两个斜杠带有Laravel 5中的可选参数 [英] Two slashes in url with optional parameters in Laravel 5

问题描述

我想在我的应用程序中创建用户的商店".默认网址为:

I want to create Users`s shop in my application. Default urls are:

site.com/cars
site.com/parts

如果用户创建自己的商店网址，如下所示:

If user create own shop urls viewed like this:

site.com/user_name/cars
site.com/user_name/parts

如果用户不创建商店，则参数 {user_name} 为空，并且URL的显示方式如下:

And if user do not create store, parameter {user_name} is empty and urls viewed like:

site.com//cars
site.com//parts

如何为此创建路由或中间件?

How can I create routes or middlewares for this?

谢谢.

UPD:

我的路线

Route::group(['domain' => 'site.com'], function () {

    Route::group(['prefix' => LaravelLocalization::setLocale(), 'middleware' => ['localeSessionRedirect', 'localizationRedirect', 'maintenance_mode']], function()
    {
        Route::group(['prefix' => '{store_name?}', 'namespace' => 'UserOnlineShop', 'middleware' => ['online_shop_tarif']], function(){
            Route::get('/', ['as' => 'user_store.home', 'uses' => 'HomeController@index']);
            Route::get('parts/', ['as' => 'parts.index', 'uses' => 'PartsViewController@all_parts']);
            Route::get('catalog/cars_for_parts', ['as' => 'catalog.auto_brands', 'uses' => 'AutoCatalogController@auto_brands']);
        });
    });
});

推荐答案

我认为您要找的是什么

Route::get('site.com/{user_name?}/cars', function ($user_name = null){

       return view
});

?使 user_name 用户名是必需的，并且 null 是必需的，并且可以是任何其他默认值.

The ? makes the user_name oprional and the null is needed and can be any other default value.

对于您的询问(使用命名控制器)，您可以通过这种方式进行.将此添加到您的路由组:

For what your asking (using named controllers) you may do it this way. Add this to your route group:

Route::get('site.com/{user_name?}/cars', ['as' => 'site.cars', 'uses' => 'CarController@car_names']);

然后在控制器中执行以下操作:

Then in controller do:

public function car_names($user_name = null){

    return view;
}

来源: laravel可选参数

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