Python，NetworkX六角形格子问题-如何创建完美的格子? [英] Python, NetworkX hexagonal lattice problem - how to create a perfect lattice?

问题描述

因此，我尝试使用Python中的NetworkX生成六边形格子.使用代码后:

  G = nx.hexagonal_lattice_graph(m = 2，n = 2，周期性= False，with_positions = True，create_using = None)plt.subplot(111)nx.draw(G，with_labels = True，font_weight ='bold')plt.show() 

我得到一个看起来像这样的六边形格子:

So I am trying to generate a hexagonal lattice using NetworkX in Python. After using code:

G = nx.hexagonal_lattice_graph(m=2, n=2, periodic=False, with_positions=True, create_using=None)
plt.subplot(111)
nx.draw(G, with_labels=True, font_weight='bold')
plt.show()

I am getting a hexagonal lattice which looks like this: lattice

As you can see, this lattice is formed from irregular hexagons and everytime the code is ran the shape changes. Is there a way to generate a perfect hexagonal lattice using NetworkX, i.e this, but with only X number of hexagons?

Thanks!

解决方案

You need to use the with_postion attribute in the hexagonal_lattic_graph function and set it to True. This will store the positions of the nodes in an attribute called pos inside the Graph G itself. You can read more about from the documentation here:

with_positions (bool (default: True)) – Store the coordinates of each node in the graph node attribute ‘pos’. The coordinates provide a lattice with vertical columns of hexagons offset to interleave and cover the plane. Periodic positions shift the nodes vertically in a nonlinear way so the edges don’t overlap so much.

So, you just need to extract the positions from the graph itself, like this:

pos = nx.get_node_attributes(G, 'pos')

Then, pass this with pos while drawing your graph

import networkx as nx
import matplotlib.pyplot as plt

# create the graph and set with_positions=True
G = nx.hexagonal_lattice_graph(m=2, n=2, periodic=False, with_positions=True, create_using=None)
plt.subplot(111)

# Extract the positions
pos = nx.get_node_attributes(G, 'pos')

# Pass the positions while drawing
nx.draw(G, pos=pos, with_labels=True, font_weight='bold')
plt.show()

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