为什么matplotlib可以外推/绘制缺失值? [英] Why does matplotlib extrapolate/plot missing values?

问题描述

我有时无法获得全部数据.我正在实时绘制传感器的值，并且可以通过用户交互来打开和关闭这些值，因此我无法确定这些值始终是连续的.用户可以启动传感器，然后将其关闭再打开，但在这种情况下，matplotlib 从最后一个终点和新起点绘制一条线.

I have a situation where sometimes, a whole series of data is not available. I'm real-time plotting values from sensors, and these can be turned on and off via user interaction, and thus I cannot be sure the values are always in a series. A user can start a sensor and later turn it off and on again, but In this case, matplotlib draws a line from the last end point and the new start point.

我绘制的数据如下:

[[  5.          22.57011604]
 [  6.          22.57408142]
 [  7.          22.56350136]
 [  8.          22.56394005]
 [  9.          22.56790352]
 [ 10.          22.56451225]
 [ 11.          22.56481743]
 [ 12.          22.55789757]
  #Missing x vals. Still plots straight line..
 [ 29.          22.55654716]
 [ 29.          22.56066513]
 [ 30.          22.56110382]
 [ 31.          22.55050468]
 [ 32.          22.56550789]
 [ 33.          22.56213379]
 [ 34.          22.5588932 ]
 [ 35.          22.54829407]
 [ 35.          22.56697655]
 [ 36.          22.56005478]
 [ 37.          22.5568161 ]
 [ 38.          22.54621696]
 [ 39.          22.55033493]
 [ 40.          22.55079269]
 [ 41.          22.55475616]
 [ 41.          22.54783821]
 [ 42.          22.55195618]]

我的绘图函数看起来简化了很多:

my plot function looks a lot simplified like this:

def plot(self, data)
    for name, xy_dict in data.iteritems():
        x_vals = xy_dict['x_values']
        y_vals = xy_dict['y_values']
        line_to_plot = xy_dict['line_number']
        self.lines[line_to_plot].set_xdata(x_vals)
        self.lines[line_to_plot].set_ydata(y_vals)

有人知道为什么会那样吗?绘图时是否必须处理非串行 x 和 y 值?看来matplotlib应该自己解决这个问题.否则，我必须将列表拆分成较小的列表并进行绘制?

Does anyone know why it does like that? And do I have to take care of non-serial x and y values when plotting? It seems matplotlib should take care of this on its own.. Otherwise i have to split lists into smaller lists and plot these?

推荐答案

一种选择是在数据丢失的地方添加虚拟项(在您的情况下，显然 x 的变化大于1)，并将它们设置为屏蔽元素.这样，matplotlib会跳过线段.例如:

One option would be to add dummy items wherever data is missing (in your case apparently when x changes by more than 1), and set them as masked elements. That way matplotlib skips the line segments. For example:

import numpy as np
import matplotlib.pylab as pl

# Your data, with some additional elements deleted...
data = np.array(
[[  5., 22.57011604],
 [  6., 22.57408142],
 [  9., 22.56790352],
 [ 10., 22.56451225],
 [ 11., 22.56481743],
 [ 12., 22.55789757],
 [ 29., 22.55654716],
 [ 33., 22.56213379],
 [ 34., 22.5588932 ],
 [ 35., 22.54829407],
 [ 40., 22.55079269],
 [ 41., 22.55475616],
 [ 41., 22.54783821],
 [ 42., 22.55195618]])

x = data[:,0]
y = data[:,1]

# Difference from element to element in x
dx = x[1:]-x[:-1]

# Wherever dx > 1, insert a dummy item equal to -1
x2 = np.insert(x, np.where(dx>1)[0]+1, -1)
y2 = np.insert(y, np.where(dx>1)[0]+1, -1)

# As discussed in the comments, another option is to use e.g.:
#x2 = np.insert(x, np.where(dx>1)[0]+1, np.nan)
#y2 = np.insert(y, np.where(dx>1)[0]+1, np.nan)
# and skip the masking step below.

# Mask elements which are -1
x2 = np.ma.masked_where(x2 == -1, x2)
y2 = np.ma.masked_where(y2 == -1, y2)

pl.figure()
pl.subplot(121)
pl.plot(x,y)
pl.subplot(122)
pl.plot(x2,y2)

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