在 Pandas 中使用 difflib SequenceMatcher 比率进行合并 [英] Using difflib SequenceMatcher ratio to merge in Pandas

查看:50
本文介绍了在 Pandas 中使用 difflib SequenceMatcher 比率进行合并的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想弄清楚是否有一种方法可以根据 difflib SequenceMatcher 比率在 Pandas 中对字符串进行模糊合并.基本上,我有两个如下所示的数据框:

I'm trying to figure out if there's a way to do fuzzy merges of string in Pandas based on the difflib SequenceMatcher ration. Basically, I have two dataframes that look like this:

df_a
company    address        merged
Apple     PO Box 3435       1

df_b
company     address
Apple Inc   PO Box 343

我想像这样合并:

df_c = pd.merge(df_a, df_b, how = 'left', on = (difflib.SequenceMatcher(None, df_a['company'], df_b['company']).ratio() > .6) and (difflib.SequenceMatcher(None, df_a['address'], df_b['address']).ratio() > .6)

有一些帖子与我正在寻找的内容相近,但没有一个适合我想做的事情.关于如何使用 difflib 进行这种模糊合并的任何建议?

There are a few posts that are close to what I'm looking for, but none of them work with what I want to do. Any suggestions on how to do this kind of fuzzy merge using difflib?

推荐答案

可能有用的方法:测试所有列值组合的部分匹配.如果有匹配项,则为 df_b 分配一个键以进行合并

Something that might work: test for partial matches for all combinations of column values. If there is a match assign a key to df_b for merging

df_a['merge_comp'] = df_a['company'] # we will use these as the merge keys
df_a['merge_addr'] = df_a['address']

for comp_a, addr_a in df_a[['company','address']].values:
    for ixb, (comp_b, addr_b) in enumerate(df_b[['company','address']].values)
        if difflib.SequenceMatcher(None,comp_a,comp_b).ratio() > .6:
            df_b.ix[ixb,'merge_comp'] = comp_a # creates a merge key in df_b
        if difflib.SequenceMatcher(None,addr_a, addr_b).ratio() > .6:
            df_b.ix[ixb,'merge_addr'] = addr_a # creates a merge key in df_b

现在可以合并了

merged_df = pandas.merge(df_a,df_b,on=['merge_addr','merge_comp'],how='inner')

这篇关于在 Pandas 中使用 difflib SequenceMatcher 比率进行合并的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆