Pymongo，查询列表字段，和/或 [英] Pymongo, query on list field, and/or

问题描述

我有一个包含一些文档的集合，例如:

<代码>{_id: 5,值:[100, 1100, 1500]},{_id: 10,值:[1100, 1700]}

如何查询具有 vals 字段的文档:

• 1100
• 1700 或 100
• 100 和 1100

我可以使用一些理解魔法，例如:

g = lambda 代码: (d for d in collection.find() 如果有的话(d["vals"] 中的代码用于代码中的代码))g([100, 1700]).next()

或者，对于 AND:

g = lambda 代码: (d for d in collection.find() if all(code in d["vals"] for code in code))g([100, 1100]).next()

这看起来有点笨拙，但如果有一些可以通过驱动程序完成的查找魔法.

解决方案

yourmongocoll.find({"vals":1100})yourmongocoll.find({"$or":[ {"vals":1700}, {"vals":100}]})yourmongocoll.find({"$and":[ {"vals":100}, {"vals":1100}]})

我建议阅读 Mongodb 高级查询

您还会找到 $in ...有用

I have a collection with some documents like:

{
    _id: 5,
    vals: [100, 1100, 1500]
},
{
    _id: 10,
    vals: [1100, 1700]
}

How can I query for documents that have, in vals field:

• 1100
• 1700 OR 100
• 100 AND 1100

I can use some comprehension magic like:

g = lambda codes: (
    d for d in collection.find() if any(code in d["vals"] for code in codes)
)
g([100, 1700]).next()

Or, for the AND:

g = lambda codes: (
    d for d in collection.find() if all(code in d["vals"] for code in codes)
)
g([100, 1100]).next()

This seems a little clunky though if there is some find magic that can be done with the driver.

解决方案

yourmongocoll.find({"vals":1100})
yourmongocoll.find({"$or":[ {"vals":1700}, {"vals":100}]})
yourmongocoll.find({"$and":[ {"vals":100}, {"vals":1100}]})

i would recommend reading Mongodb Advanced queries

you will also find $in ...useful

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