执行二进制包 [英] executing wrapped binary

问题描述

我想执行包裹着我自己的组装code里面的二进制，有理由像我想要做一些init和查看二进制的行为，但我无法执行二进制即使没有任何这样的init上UART无输出，LCD（我运行一个基于ARM cortexa-8 qs​​d8250b芯片组供电的MDP [移动开发平台]）我知道我的船上包装的二进制完美运行，因为我已经用它早期（不到一天前）。

I am trying to execute a binary wrapped inside my own assembly code, there are reasons like i want to do some init and see how the binary behaves, however i am unable to execute the binary even without any such init, no output on uart, lcd (I am running an arm cortexa-8 based qsd8250b chipset powering a mdp[mobile development platform]) I know the wrapped binary runs perfectly on my board since i have used it earlier (less than a day ago).

问题是，我不确定/信息不可用有关，其中二进制加载到内存中。

Problem is, i am unsure/info is not available regarding where the binary is loaded in memory.

这是我的code到目前为止

This is my code so far

.org 0
.type _start,#function
.globl _start
_start:
   b   main
@@ Snipped headers @@
.org   0x1000
main:
   mov r9, pc             @r9= address of loadlk in memory
   ldr r2, =loadlk        @r2= address of loadlk in objfile
loadlk:
   sub r0, r9, r2         @r0= r9-r2 = address of _start in memory
   add r0, r0, #0x1200    @r0= r0 + 0x1200 = lkbin_start (src)
   add r3, r0, #0xD000    @r3= r0 + 0xd000 = lkbin_start + ~sz(lk.bin) = lkbin_end (end)
cpy:
   ldr r1, =0x28000000    @r1= destination (dst)
   ldr r2, [r0],#4
   str r2, [r1],#4
   cmp r0, r3             @current read address ?= end, r0 < r3 -> branch back
   blo cpy
   ldr r9, =0x28000000
   ldr r4, =0xa9000864    @Flashlight
   ldr r5, =0xa9000814
   ldr r4, [r4, #0]
   orr r6, r4, #0x200000
   str r6, [r5, #0]
   dsb sy
   isb sy
   bx  r9
   b   .
.ltorg
.org 0x1200
lkbin_start:
.incbin  "lk.bin"
lkbin_end:
.align 8

这是我的编译脚本

and this is my compile script

arm-none-eabi-as bootwrapper.S -o bootwrapper.o
arm-none-eabi-objcopy -O binary bootwrapper.o binary

这肯定不会达到手电筒code，因为我看到我的手电筒闪烁，但没有任何反应，从我能想到它会将垃圾code到目标，并试图执行它。

It sure does reach the flashlight code as i see my flashlight blink, but then nothing happens, from what i can think it copies trash code to the target and tries to execute it.

任何帮助吗？

推荐答案

好吧，我不知道我可能是这个愚蠢的夜晚...

Okay, i didn't know i could be this silly at night...

cpy:
   ldr r1, =0x28000000    @r1= destination (dst)
   ldr r2, [r0],#4
   str r2, [r1],#4
   cmp r0, r3             @current read address ?= end, r0 < r3 -> branch back
   blo cpy

随着循环继续，R1总是覆盖previous内容的值0x28000000，因此所有的数据在内存中写入一个单一的位置......多么的愚蠢。

As the loop went on, r1 always had the value 0x28000000, so all data was written to one single location in memory overwriting the previous contents... how stupid.

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