我怎么能计算两个的ArrayList的区别? [英] How can I calculate the difference between two ArrayLists?
问题描述
我有两个的ArrayList
I have two ArrayLists.
ArrayList中A包含
ArrayList A contains
['2009-05-18','2009-05-19','2009-05-21']
ArrayList的B中<$c$c>['2009-05-18','2009-05-18','2009-05-19','2009-05-19','2009-05-20','2009-05-21','2009-05-21','2009-05-22']$c$c>
我要比较ArrayLst A和ArrayLst B点。结果的ArrayList
应含有不ArrayList中存在A.名单
ArrayList的结果应该是
I have to compare ArrayLst A and ArrayLst B . The result ArrayList should contain the List which does not exist in ArrayList A. ArrayList result should be
['2009-05-20','2009-05-22']
['2009-05-20','2009-05-22']
如何比较?
推荐答案
在Java中,你可以使用<$c$c>Collection$c$c>接口的<一个href=\"http://docs.oracle.com/javase/8/docs/api/java/util/Collection.html#removeAll-java.util.Collection-\"><$c$c>removeAll$c$c>方法。
In Java, you can use the Collection
interface's removeAll
method.
// Create a couple ArrayList objects and populate them
// with some delicious fruits.
Collection firstList = new ArrayList() {{
add("apple");
add("orange");
}};
Collection secondList = new ArrayList() {{
add("apple");
add("orange");
add("banana");
add("strawberry");
}};
// Show the "before" lists
System.out.println("First List: " + firstList);
System.out.println("Second List: " + secondList);
// Remove all elements in firstList from secondList
secondList.removeAll(firstList);
// Show the "after" list
System.out.println("Result: " + secondList);
以上code将产生以下的输出:
The above code will produce the following output:
First List: [apple, orange]
Second List: [apple, orange, banana, strawberry]
Result: [banana, strawberry]
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