我怎么能连接两个属性到一个属性使用休眠条件查询 [英] how can i concatenate two properties into one property using hibernate criteria query
问题描述
,房子号码是10,pincode是110064,地址属性是10,110064
这是我的代码
final Criteria criteria = getDatabaseSession()。createCriteria(Application.class,application);
final ProjectionList projectionList = Projections.projectionList();
criteria.setProjection(projectionList);
projectionList.add(Projections.property(address.street),street);
projectionList.add(Projections.property(address.postcode),postcode);
projectionList.add(Projections.property(address.houseNumber),houseNumber);
criteria.createAlias(application.applicationCase,applicationCase,JoinType.INNER_JOIN);
criteria.createAlias(applicationCase.property,property);
criteria.createAlias(property.address,address);
criteria.setResultTransformer(Criteria.ALIAS_TO_ENTITY_MAP);
return(Map< String,Object>)criteria.uniqueResult();
我想做这样的事情
projectionList.add(Projections.property(address.street+address.houseNumber+address.postcode),address);
有人可以帮忙。
concat
表达式,但它只能用于HQL select concat(address.street,address.houseNumber,address.postcode)as fullAddress from ...
使用@Formula
如果您想使用 Criteria,
,您可以使用 @Formula
。需要为持久
@Formula(value =concat(f_street,f_houseNumber,f_postcode))添加额外的属性。
private String fullAddress;
您需要指定列名称(不是属性名称),因为Hibernate将它们添加到SQL中是。使用连接时不太方便 - 您需要在公式中指定由Hibernate生成的别名。
您可以参考 Projection
中的 fullAddress
projectionList.add(Projections.property(fullAddress),fullAddress);
我用MySQl测试了它。对于Oracle,您可以尝试使用
@Formula(value =f_street || f_houseNumber || f_postcode)
私人字符串fullAddress;
扩展Hibernate
我试图扩展 Projection
以将 concat
函数添加到 Criteria
。我测试它是最简单的情况。
public class ConcatProjection extends SimpleProjection {
private static final String CONCAT_FUNCTION_NAME =concat;
private final String [] properties;
public ConcatProjection(String ... properties){
this.properties = properties;
$ b @Override
public String toSqlString(Criteria criteria,int loc,CriteriaQuery criteriaQuery)
抛出HibernateException {
String result = getFunction(criteriaQuery) .render(StringType.INSTANCE,
propertiesToColumns(criteria,criteriaQuery),criteriaQuery.getFactory());
返回结果+as y+ loc +'_';
}
私人列表< String> propertiesToColumns(Criteria criteria,CriteriaQuery criteriaQuery){
List< String> result = new ArrayList< String>(properties.length);
for(String property:properties){
result.add(criteriaQuery.getColumn(criteria,property));
}
返回结果;
}
private SQLFunction getFunction(CriteriaQuery criteriaQuery){
return criteriaQuery.getFactory()。getSqlFunctionRegistry()
.findSQLFunction(CONCAT_FUNCTION_NAME);
$ b @Override
public Type [] getTypes(Criteria criteria CriteriaQuery criteriaQuery)
抛出HibernateException {
return new Type [] {StringType。 INSTANCE};
}
}
使用
projectionList.add(
new ConcatProjection(address.street,
address.houseNumber,address.postcode ), 完整地址);
for example there are 2 properties house number and pincode and i want a single property as address like house number is 10 and pincode is 110064 and combine address property is 10,110064 this is my code
final Criteria criteria= getDatabaseSession().createCriteria(Application.class, "application");
final ProjectionList projectionList=Projections.projectionList();
criteria.setProjection(projectionList);
projectionList.add(Projections.property("address.street"), "street");
projectionList.add(Projections.property("address.postcode"), "postcode");
projectionList.add(Projections.property("address.houseNumber"), "houseNumber");
criteria.createAlias("application.applicationCase", "applicationCase", JoinType.INNER_JOIN);
criteria.createAlias("applicationCase.property", "property");
criteria.createAlias("property.address", "address");
criteria.setResultTransformer(Criteria.ALIAS_TO_ENTITY_MAP);
return (Map<String, Object>) criteria.uniqueResult();
and i want to do something like this
projectionList.add(Projections.property("address.street"+"address.houseNumber"+"address.postcode"),"address");
can somebody help.
Using HQL
You can use the concat
expression, but it can be used only with HQL
select concat(address.street, address.houseNumber, address.postcode) as fullAddress from ...
Using @Formula
If you want to use Criteria,
you can use @Formula
. It is need to add additional property to the persistent
@Formula(value = "concat(f_street, f_houseNumber, f_postcode)")
private String fullAddress;
You need to specify column names (not property names), because of Hibernate adds them to the SQL as is. It is not very convenient when you use joins — you need to specify aliases, generated by Hibernate, in the formula.
You can refer to the fullAddress
in the Projection
projectionList.add(Projections.property("fullAddress"), "fullAddress");
I have tested it with MySQl. For Oracle you can try to use
@Formula(value = "f_street || f_houseNumber || f_postcode")
private String fullAddress;
Extending Hibernate
I have tried to extend the Projection
to add concat
function to the Criteria
. I test it for the simplest case.
public class ConcatProjection extends SimpleProjection {
private static final String CONCAT_FUNCTION_NAME = "concat";
private final String[] properties;
public ConcatProjection(String... properties) {
this.properties = properties;
}
@Override
public String toSqlString(Criteria criteria, int loc, CriteriaQuery criteriaQuery)
throws HibernateException {
String result = getFunction(criteriaQuery).render(StringType.INSTANCE,
propertiesToColumns(criteria, criteriaQuery), criteriaQuery.getFactory());
return result + " as y" + loc + '_';
}
private List<String> propertiesToColumns(Criteria criteria, CriteriaQuery criteriaQuery) {
List<String> result = new ArrayList<String>(properties.length);
for (String property : properties) {
result.add(criteriaQuery.getColumn(criteria, property));
}
return result;
}
private SQLFunction getFunction(CriteriaQuery criteriaQuery) {
return criteriaQuery.getFactory().getSqlFunctionRegistry()
.findSQLFunction(CONCAT_FUNCTION_NAME);
}
@Override
public Type[] getTypes(Criteria criteria, CriteriaQuery criteriaQuery)
throws HibernateException {
return new Type[] { StringType.INSTANCE };
}
}
Using
projectionList.add(
new ConcatProjection("address.street",
"address.houseNumber", "address.postcode"), "fullAddress");
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