在 nmutablearray 中单独的未来日期 [英] separate future date in nsmutablearray
问题描述
我在该数组中有一个可变数组,我只有过去的日期、当前日期和未来日期.我必须分开未来的日期 &存储到另一个数组中.你能帮我吗.
I am having a mutable array in that array i am having only past date, current date & future date. I have to separate the future date & store into another array. Can you help me.
这是我的数组:
uniqueItems(
"2015-03-01",
"2015-02-28",
"2015-02-22",
"2015-02-21",
"2015-02-20",
"2015-02-15",
"2015-02-14",
"2015-02-13",
"2015-02-08",
"2015-02-07",
"2015-02-01",
"2015-01-31",
"2015-01-30",
"2015-01-25",
"2015-01-24",
"2015-01-18",
"2015-01-17",
"2015-01-16",
"2015-01-11",
"2015-01-10",
"2014-12-07"
我已经尝试过这种编码,但不起作用.
I have tried this coding, but is not working.
NSDate *currentDate = [NSDate date];
NSDate* dateAdded=(NSDate*)[uniqueItems objectAtIndex:0];
double min = [currentDate timeIntervalSinceDate:dateAdded];
int minIndex = 0;
for (int i = 1; i < [uniqueItems count]; ++i)
{
double currentmin = [currentDate timeIntervalSinceDate:[uniqueItems objectAtIndex:i]];
if (currentmin < min) {
min = currentmin;
minIndex = i;}}
推荐答案
你可以使用 NSPredicate
块.您的数组不包含 NSDate
对象,因此我们需要将其转换为 NSDate
然后与 [NSDate date]
you can use NSPredicate
block for that. your array does not contain NSDate
objects so we need to convert it into NSDate
and then compare with [NSDate date]
NSPredicate *findFutureDates = [NSPredicate predicateWithBlock: ^BOOL(id obj, NSDictionary *bind){
NSDateFormatter *df = [[NSDateFormatter alloc]init];
[df setDateFormat:@"yyyy-MM-dd"];
[df setTimeZone:[NSTimeZone systemTimeZone]];
NSDate *dd = [df dateFromString:(NSString *)obj ];
return ([[NSDate date] compare:dd] == NSOrderedAscending);
}];
NSArray *arrFutureDates = [yourArray filteredArrayUsingPredicate: findFutureDates];
NSLog(@"%@",arrFutureDates);
如果你通过了 NSOrderedAscending
会给你未来的日期如果你通过 NSOrderedDescending
会给你过去的日期.
if you pass NSOrderedAscending
will give you future dates if you pass NSOrderedDescending
will give you past dates.
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