NSInteger 错误的隐式转换 [英] Implicit conversion of NSInteger error

问题描述

使用 MagicalRecord，我尝试使用特定的 clientNumber 获取记录，该记录是一个 NSInteger(定义为 int16 作为数据类型).

Using MagicalRecord, I am trying to get the record with a particular clientNumber which is a NSInteger (defined as int16 as the data type).

这是我收到错误的代码行:

This is my line of code where I'm getting the error:

ClientInfo *clientSelected = [ClientInfo MR_findFirstByAttribute:@"aClientNumber" withValue: clientNumber inContext:localContext];

更新:这是 MR_findFirstByAtytribute 的定义:

UPDATE: This is the definition of MR_findFirstByAtytribute:

MR_findFirstByAttribute:(NSString *) withValue:(id)

这是我得到的错误:

Implicit conversion of NSInteger (aka int) is disallowed with ARC

就我的一生而言，我看不出有什么问题.ClientInfo 定义为

For the life of me, I don't see what's wrong. ClientInfo is defined as

@interface ClientInfo : NSManagedObject

推荐答案

withValue 的参数类型是一个 id(一个指针).NSInteger 是标量值(不是对象)，不能隐式转换为指针值.

The parameter type for withValue is an id (a pointer). NSInteger is a scalar value (not an object) and cannot be converted to a pointer value implicitly.

这纯粹是一个猜测，但从 NSInteger 创建一个 NSNumber 可能会起作用:

This is purely a guess, but creating an NSNumber from the NSInteger might work:

NSNumber *val = [NSNumber numberWithInteger:clienNumber]
ClientInfo *clientSelected = [ClientInfo MR_findFirstByAttribute:@"aClientNumber" withValue:val inContext:localContext];

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