有没有办法在 Swift 中声明内联函数? [英] Is there a way to declare an inline function in Swift?

问题描述

我对 Swift 语言非常陌生.

我想声明一个 inline 函数，就像在 C++ 中一样所以我的 func 声明如下所示:

func MyFunction(param: Int) ->整数{...}

我想做这样的事情:

inline func MyFunction(param: Int) ->整数{...}

我尝试在网上搜索，但没有找到任何相关内容，也许没有 inline 关键字，但也许有另一种方法可以在 Swift 中内联该函数.

解决方案

Swift 1.2 将包含 @inline 属性，带有 never 和 __always> 作为参数.有关详细信息，请参阅此处.>

如前所述，您很少需要将函数显式声明为 @inline(__always)，因为 Swift 在何时内联函数方面相当聪明.但是，在某些代码中可能需要不内联函数.

Swift 5 添加了 @inlinable 属性.确保你阅读了它，因为可能有几个问题可能会导致无法使用.它也仅适用于声明为 public 的函数/方法，因此它适用于那些希望为链接到您的库的那些公开内联内容的人.

I'm very new to the Swift language.

I wanted to declare an inline function just like in C++ so my func declaration looks like this:

func MyFunction(param: Int) -> Int {
    ...
}

and I want to do something like this:

inline func MyFunction(param: Int) -> Int {
    ...
}

I tried to search on the web but I didn't find anything relevant maybe there is no inline keyword but maybe there is another way to inline the function in Swift.

解决方案

Swift 1.2 will include the @inline attribute, with never and __always as parameters. For more info, see here.

As stated before, you rarely need to declare a function explicitly as @inline(__always) because Swift is fairly smart as to when to inline a function. Not having a function inlined, however, can be necessary in some code.

Edit: Swift 5 added the @inlinable attribute. Make sure you read up about it, as there may be a couple of gotchas that might make in unusable. It's also only for functions/methods declared public, so it's meant for those wanting to expose inline stuff for those that link to your library.

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