将字符串解析为结构变量 [英] Parsing String into struct variables
本文介绍了将字符串解析为结构变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试将一个字符串解析为一个包含不同变量的结构向量.这是我到目前为止所拥有的,但似乎不起作用.
Im trying to parse a string into a vector of a struct that has different variables in it. This is what I have so far but it doesnt seem to work.
struct client
{
string PhoneNumber;
string FirstName;
string LastName;
string Age;
};
int main()
{
string data = getClientDatabase();
vector <client> clients;
parse_string(data, clients);
return 0;
}
string getClientDatabase()
{
return
"(844)615-4504 Sofia Ross 57 \n"
"(822)516-8895 Jenna Doh 30 \n"
"(822)896-5453 Emily Saks 43 \n"
}
所以我写的这个函数似乎不起作用,我确定有更简单的方法,但我无法弄清楚.
So this function I wrote doesnt seem to work, im sure there is an easier way but i cant figure it out.
void parse_string(string data, vector <client> &clients)
{
string temp;
string temp1;
string temp2;
string temp3;
int i = 0;
int j = 0;
int k = 0;
int l = 0;
while (i < data.length())
{
if (data.at(i) != ' ')
{
temp.push_back(data.at(i));
j++;
}
else
{
clients.at(i).PhoneNumber = temp;
}
}
if (data.at(j) != ' ')
{
temp1.push_back(data.at(j));
k++;
}
else
{
clients.at(i).FirstName = temp1;
}
if (data.at(k) != ' ')
{
temp2.push_back(data.at(k));
l++;
}
else
{
clients.at(i).LastName = temp2;
}
if (data.at(l) != ' ')
{
temp3.push_back(data.at(l));
}
else
{
clients.at(i).Age = temp3;
}
i++;
}
推荐答案
尝试使用 istringstream
对象:
void parse_string(string data, vector <client> & clients) {
istringstream iss(data);
for (size_t i=0; iss >> clients.at(i).PhoneNumber; ++i) {
iss >> clients.at(i).FirstName
>> clients.at(i).LastName
>> clients.at(i).Age;
}
}
这篇关于将字符串解析为结构变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文