用令牌解析字符串的函数 [英] Function to parse string with tokens

问题描述

我知道如何在 C# 和 VB 中编程，但不知道如何使用 C++，并且必须为使用 C++ 的条码扫描器编写一个小 exe :(

I know how to program in C# and VB but not have idea about how to use C++ and have to program a little exe to a barcode scanner that use C++ :(

此时，我尝试解析具有多个以/"分隔的数据的扫描条码，我发现存在一个 strtok 函数，手动"对其进行了测试并且工作正常，但我还没有实现一个可以调用的工作函数正确，我现在拥有的:

In this moment I try to parse a scanned barcode that have multiple data sepparated with a "/", I find that exist a strtok function, tested it "manually" and worked ok but I not implemented yet a working function to call it correctly, what I have now:

#include <string.h>
#include <stdio.h>
#include <stdlib.h>

int elemStr(char *str, char sep)
{
   int cantElem;
   unsigned ich;

   cantElem = 0;

   if (strlen(str) > 0) //at least 1 elem
      cantElem++;

   for (ich = 0; ich < strlen(str); ich++)
   {         
      if (str[ich] == sep)
         cantElem++;      
   }                
   return cantElem;
}

char* getElemStr(char *str, char sep[], int elem)
{   
    char *tempStr = NULL;
    char *tok;                   
    int currElem = 1;

    // 1st data
    strcpy( tempStr, str);
    tok = strtok( tempStr, sep);

    while( currElem != elem )
    {       
        // Get next tokens:
        tok = strtok( NULL, sep );
        currElem++;
    }

    return tok;
}


void main( void )
{
    char barcode[] = "710015733801Z/1/35";

    char sep[] = "/";
    char sep1 = sep[0];

    char barcd[20];
    char piezaChar[4];
    int pieza;
    char mtsChar[4];

    int cantElem;

    cantElem = elemStr(barcode, sep1 );

    if (cantElem >= 1)
    {
        strcpy(barcd, getElemStr(barcode,sep,1) ); //pasa a str resultado;
        printf("Cod: %s\n", barcd ); //STACK OVERFLOW HERE!
    }
 }

如果我在没有函数getElemStr"的情况下使用 strtok 它可以正常工作，但我也尝试在其他地方使用它.

if I use strtok witout a function "getElemStr" it work ok but I try to use it on other places too.

我可以这样使用 strtok 吗?你有一个工作例子吗?pd:我不知道指针(抱歉)，了解这个的好文档?

Can I use strtok like this? You have a working example? pd: I not have idea about pointers (sorry), good doc to learn about that?

推荐答案

这是一个不使用 boost 的 C++ 解决方案.

Here is a C++ solution that doesn't use boost.

#include <string>
#include <sstream>
#include <iostream>

int main()
{
    std::string barcode = "710015733801Z/1/35";

    std::stringstream ss(barcode);
    std::string elem;

    while(std::getline(ss, elem, '/'))
    {
        //do something else meaningful with elem
        std::cout << elem << std::endl;
    }

    return 0;
}

输出:

710015733801Z
1
35

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