PowerShell - 删除文本文件的所有行，直到找到某个字符串 [英] PowerShell - Remove all lines of text file until a certain string is found

问题描述

我目前有一个输出日志文件，它有点乱，而且增长很快.这是许可邮箱的大型脚本的调试输出.我基本上只想删除文件中的每一行，直到找到 7 天前日期的第一次迭代.

I currently have an output log file that's a bit of a mess and grows quickly. It's the debug output for a large script that permissions mailboxes. I basically just want to delete every line in the file until it finds the first iteration of the date 7days ago.

到目前为止，我可以返回包含该日期的所有行

So far, I can return all lines containing that date

$content = Get-Content $file
$lastweek = "{0:M/d/yyyy}" -f (get-date).AddDays(-7)

$content | Where-Object { $_.Contains("$lastweek") }

但是我想不出一个功能来擦除所有内容，直到第一次找到为止.

But I can not figure out a function to just wipe everything until that is found for the first time.

我试过 -replace:

I have tried a -replace:

$content -replace ".*$lastweek", " " | Set-Content $file -Force

但这似乎只是从包含指定字符串的每一行的开头替换.

But that only seems to replace from the beginning of each line that contains the specified string.

推荐答案

如果您运行的是 V4，则可以使用数组 .Where() 方法，以及 'SkipUntil' 选项:

If you're running V4, you can use the array .Where() method, with the 'SkipUntil' option:

$content.Where({ $_ -like "*$lastweek*" },'SkipUntil')

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