如何读取文本文件并在冒号之前搜索某个字符串，然后在冒号之后显示内容? [英] How to read a text file and search for a certain string before a colon and then show the content after the colon?

问题描述

我有一个包含以下内容的文件:

I have a file that contains something like this:

test:fOwimWPu0eSaNR8
test2:vogAqsfXpKzCfGr

我希望能够在文件中搜索test，并将:之后的字符串设置为变量，以便可以显示，使用等.

I would like to be able to search the file for say test and it set the string after the : to a variable so it can be displayed, used etc.

这是我到目前为止用于在文件中查找测试"的代码.

Here is the code I have so far for finding 'test' in the file.

$file = 'file.txt';
$string = 'test';

$searchFile = file_get_contents($file);
if (preg_match('/\\b'.$string.'\\b/', $searchFile)) {
    echo 'true';
    // Find String
} else {
    echo 'false';
}

我该怎么做?

推荐答案

这应该对您有用:

只需使用file()将文件放入数组，然后简单地preg_grep()所有行(在冒号前都有搜索字符串)即可.

Just get your file into an array with file() and then simply preg_grep() all lines, which have the search string before the colon.

<?php

    $file = "file.txt";
    $search = "test";

    $lines = file($file, FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES);

    $matches = preg_grep("/^" . preg_quote($search, "/") . ":(.*?)$/", $lines);
    $matches = array_map(function($v){
        return explode(":", $v)[1];
    }, $matches);

    print_r($matches);

?>

输出:

Array ( [0] => fOwimWPu0eSaNR8 )

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