你能将向量传递给可变参数吗?:向量到 sprintf [英] Can you pass a vector to a vararg?: Vector to sprintf

问题描述

假设我有一个接受可变参数的函数，例如 sprintf().我想要类似的东西:

Let's say I have a function that takes variable arguments, such as sprintf(). I want something like:

sprintf("%s %s", "a", "b")

但我在向量 c("a", "b") 中有 "a" 和 "b".像

but I have "a" and "b" in a vector c("a", "b"). A call such as

sprintf("%s %s", c("a", "b"))

将因参数不足而产生错误.许多语言提供了一种将向量展平"为可变长度参数的方法.但我似乎无法在 R 中找到这样做的语法.有办法吗?

will produce an error for not enough arguments. Many languages provide a way to "flatten" a vector into a variable-length argument. But I cannot seem to find the syntax for doing so in R. Is there a way?

推荐答案

可以使用do.call:

vec <- c("a","b")
do.call(sprintf, c(list("%s %s"), vec))
# [1] "a b"

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