如何保存在C 3D数组？ [英] How are 3D arrays stored in C?

问题描述

据我了解，在C数组按行优先顺序分配。因此，对于一个2×3阵列

I understand that arrays in C are allocated in row-major order. Therefore, for a 2 x 3 array:

0  1
2  3
4  5

存储在内存中的

0 1 2 3 4 5

但是，如果我有一个2×3×2数组：

However, what if I have a 2 x 3 x 2 array:

0  1
2  3
4  5

和

6  7
8  9
10 11

如何在这些存储在内存中？只是连续这样的：

How are these stored in memory? Is just consecutive like:

0 1 2 3 4 5 6 7 8 9 10 11

或者是一些其他的方式？或者它取决于什么？

Or is it some other way? Or does it depend on something?

推荐答案

所有的尺寸被连续存储在内存中。

All "dimensions" are stored consecutively in memory.

考虑

    int arr[4][100][20];

你可以说改编[1] 和改编[2] （类型为 INT [100] [20] ）是连续的结果
或改编[1] [42] 和改编[1] [43] （类型为 INT [20] ）是连续的结果
或改编[1] [42] [7] 和改编[1] [42] [8] （类型 INT ）是连续的。

you can say that arr[1] and arr[2] (of type int[100][20]) are contiguous
or that arr[1][42] and arr[1][43] (of type int[20]) are contiguous
or that arr[1][42][7] and arr[1][42][8] (of type int) are contiguous

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