在普罗米修斯中按年/月/日对数据进行分组 [英] Group data by year/month/day in prometheus

问题描述

正如标题所说，我正在寻找一种方法来获得每天重置的时间序列的最大值.完成此任务后，我想对这些值进行总和，以获得每月/每年的值.在 Prometheus 中实现这一目标的最佳方法是什么?

As the title says, I am looking for a way to get the maximum value of a time series, which resets daily. After this task is achieved I would like to create a sum over those values to get a value per month/year. What is the best way to achieve this in Prometheus?

推荐答案

如我在 prometheus-developers，这是一个可能的选项，尽管它远非可读:

As described in my post on prometheus-developers, here is a possible option, although it's far from readable:

up{job="prometheus"} + ignoring(year, month, day) group_right
  count_values without() ("year", year(timestamp(
    count_values without() ("month", month(timestamp(
      count_values without() ("day", day_of_month(timestamp(
        up{job="prometheus"}
      )))
    )))
  ))) * 0

用您需要的任何系列选择器替换 up{job="prometheus"} 的两个实例.不过，不知道这有多有效.:o)

Replace both instances of up{job="prometheus"} with whatever series selector you need. No idea how efficient this is, though. :o)

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