红宝石：解析字符串再嵌套数组的presentation成一个阵列？ [英] Ruby: Parsing a string representation of nested arrays into an Array?

问题描述

比方说，我有字符串

"[1,2,[3,4,[5,6]],7]"

我将如何解析到数组

How would I parse that into the array

[1,2,[3,4,[5,6]],7]

嵌套结构和模式是在我的使用情况下，完全是任意的。

Nesting structures and patterns are completely arbitrary in my usage case.

我目前的临时解决方案涉及每一个时期后加空格和使用 YAML.load ，但我希望有可能的话一个更清洁的。

My current ad-hoc solution involves adding a space after every period and using YAML.load, but I'd like to have a cleaner one if possible.

（一不需要外部库如果可能的话）

(One that does not require external libraries if possible)

推荐答案

这特殊的例子被正确解析使用 JSON ：

That particular example is being parsed correctly using JSON:

s = "[1,2,[3,4,[5,6]],7]"
#=> "[1,2,[3,4,[5,6]],7]"
require 'json'
#=> true
JSON.parse s
#=> [1, 2, [3, 4, [5, 6]], 7]

如果不工作，你可以尝试运行通过 评估字符串 ，但你必须确保没有实际红宝石code已经过去了，因为评估可作为注入漏洞

If that doesn't work, you can try running the string through eval, but you have to ensure that no actual ruby code has been passed, as eval could be used as injection vulnerability.

编辑：这是一个简单的递归的，基于正则表达式解析器，没有验证，没有测试，不用于生产用途等：

Here is a simple recursive, regex based parser, no validation, not tested, not for production use etc:

def my_scan s
  res = []
  s.scan(/((\d+)|(\[(.+)\]))/) do |match|
    if match[1]
      res << match[1].to_i
    elsif match[3]
      res << my_scan(match[3])
    end
  end
  res
end

s = "[1,2,[3,4,[5,6]],7]"
p my_scan(s).first #=> [1, 2, [3, 4, [5, 6]], 7]

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