从红宝石字符串数组的序列获得的一组数字 [英] Obtain a set of numbers from a sequence of arrays of strings in ruby

问题描述

我有一个字符串数组是如下：

  B = [昨日：40，今天：20，变化：+3，changes_2：10.00％，高：30，低： 20]
 

我怎么会从阵列获取的设定值40,20的，+ 3，10.00％，30和20

我已经做了

  C = {b.map | N | n.split（）}
 

返回

  [昨天，40] [今天，20]，[变，3]，[changes_2 ：，10.00％]，[高，30]，[低，20]
 

解决方案块返回之前

刚指数拆分数组：

 ＆GT; C = {b.map | N | n.split（：）[1]}
= GT; [40，20，+ 3，10.00％，30，20]
 

I have an array of strings which is as follows

b=["yesterday: 40", "today: 20", "change: +3", "changes_2: 10.00%", "high: 30", "low: 20"]

How would I obtain the set of values 40,20,+3, 10.00%, 30 and 20 from that array

I've done

 c = b.map {|n| n.split(" ")}

That returns

 [["yesterday:", "40"], ["today:", "20"], ["change:", "+3"], ["changes_2:", "10.00%"], ["high:", "30"], ["low:", "20"]]

解决方案

Just index the split array before returning it in the block:

> c = b.map {|n| n.split(": ")[1]}
=> ["40", "20", "+3", "10.00%", "30", "20"]

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