类型错误:预期的整数参数,得到浮点数,python 3.6.3 with pygame [英] TypeError: integer argument expected, got float, python 3.6.3 with pygame

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问题描述

我的 Python 游戏有问题,这是我的第一个项目.我收到一个错误(类型错误:预期的整数参数,得到浮点数).当我插入我的用户定义函数拍摄时,它开始出现.如何解决这个问题或者让SuperMario图像拍摄一个带有类的圆形物体.谢谢:)

I am having problem with my python game, it's my first project. I am getting an error (TypeError: integer argument expected, got float). It's starting to come when I insert my user-defined function shoot. How to solve this problem or make a SuperMario image shoot a circular object with a class. Thanks :)

import pygame
import time

pygame.init()

display_height = 600
display_width = 800

white = (255,255,255)

gameDisplay = pygame.display.set_mode((display_width, display_height))
pygame.display.set_caption('Igra1')
clock = pygame.time.Clock()

bg = pygame.image.load('background.jpg')
bg = pygame.transform.scale(bg,(800, 600))

Img_SuperMario = pygame.image.load('SuperMario.png')
SuperMario_width = 611
SuperMario_height = 611
Img_SuperMario = pygame.transform.scale(Img_SuperMario, (100, 100))

def shoot(xshoot):
    while xshoot < display_width:
        pygame.draw.circle(gameDisplay, white, (xshoot,50), 20 ,0)
        xshoot += 10

def SuperMario(x,y):
    gameDisplay.blit(Img_SuperMario,(x,y))

def gameloop():

x = (display_width * 0.1)
y = (display_height * 0.1)

x_change = 0
y_change = 0

game_exit = False

while not game_exit:

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()

        if event.type == pygame.KEYDOWN:
            if  event.key == pygame.K_LEFT:
                x_change = -5
            elif event.key == pygame.K_RIGHT:
                x_change = 5
            elif event.key == pygame.K_UP:
                y_change = -5
            elif event.key == pygame.K_DOWN:
                y_change = 5

        if event.type == pygame.KEYUP:
            if event.key == pygame.K_LEFT or event.key == pygame.K_RIGHT or event.key == pygame.K_DOWN or event.key == pygame.K_UP:
                x_change = 0
                y_change = 0


    if x == display_width - 100 or x == 0:
        x_change = 0

    if y == (display_height - 100) or y == 0:
        y_change = 0


    x += x_change
    y += y_change
    xshoot = x

    gameDisplay.fill(white)
    gameDisplay.blit(bg,(0,0))

    if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                while xshoot < display_width:
                    shoot(x)
    SuperMario(x,y)

    pygame.display.update()
    clock.tick(60)

gameloop()
pygame.quit()
quit()

推荐答案

pygame.draw.circle 函数只接受整数,但你的 x 变量是一个浮点数.在 shoot 函数中将 xshoot 变量转换为整数,例如:

The pygame.draw.circle function only accepts integers, but your x variable is a float. Convert the xshoot variable to an integer in the shoot function, e.g.:

pygame.draw.circle(gameDisplay, white, (int(xshoot), 50), 20 ,0)

看起来您还需要更改 while xshoot <display_width: 在主循环和 shoot 函数中循环,但我不确定你想要实现什么.

It looks like you also need to change the while xshoot < display_width: loops in the main loop and the shoot function, but I'm not sure what you want to achieve.

这篇关于类型错误:预期的整数参数,得到浮点数,python 3.6.3 with pygame的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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