Python 3.3.3:类型错误:列表索引必须是整数，而不是浮点数 [英] Python 3.3.3: TypeError: list indices must be integers, not float

问题描述

我有一个 python 2.7.6 程序，我想转换为 3.3.3.

I have a python 2.7.6 program I want to convert to 3.3.3.

我收到一个错误:

File "H:\My Game Python 3,3\MoonSurvival.py", line 199, in run
  self.moon.levelStructure[x][y] = None

回溯是:

Traceback (most recent call last):
  File "H:\My Game Python 3,3\MoonSurvival.py", line 591, in <module>
    Game().run()
  File "H:\My Game Python 3,3\MoonSurvival.py", line 199, in run
    self.moon.levelStructure[x][y] = None
TypeError: list indices must be integers, not float

但是当我查看 levelStructure 的代码时，没有任何问题.这是分配 levelStructure 的代码:

But when I look at the code for the levelStructure there is nothing wrong. This is the code that assigns levelStructure:

tempBlock = Block(x*64, y*64)
# add block to both and self.levelStructure
self.levelStructure[x][y] = tempBlock

如您所见，levelStructure 是 tempBlock.随着它的乘法，它似乎给出了一个浮动.我知道除法是两个斜线 /.我试图乘以 '*' 但我仍然得到错误.我不完全熟悉 3.3.3 语法，因为我通常使用 2.7.6.

As you can see the levelStructure is tempBlock. As it is multiplying, it seems to be giving a float. I know with division it is two slashes /. I have tried to multiply '*' but I still get the error. I am not entirely familiar with 3.3.3 syntax as I generally use 2.7.6.

块代码:

class Block(pygame.sprite.Sprite):
    def __init__(self, x, y):
        pygame.sprite.Sprite.__init__(self)

        self.image = pygame.image.load('data/images/moon.jpg')

        self.rect = self.image.get_rect()
        self.rect.x = x
        self.rect.y = y

    def render(self, surface):
        surface.blit(self.image, self.rect)

导致此错误的原因是什么?

What causes this error?

推荐答案

由于您正在从 Python 2.7 -> Python 3.x 转换，这几乎肯定是楼层划分的问题.

Since you're converting from Python 2.7 -> Python 3.x, it's almost CERTAINLY an issue with floor division.

我不确定您在何处生成 x 和 y，但是如果您在任何时候将这些数字除以任何值，请确保使用// Python 3 中的运算符，如果您希望得到一个整数结果.

I'm not sure where exactly you're generating your x and y, but if at any point you divide those numbers by anything, make sure you use the // operator in Python 3 if you expect an integer result.

在 Python 2 中，5/2 == 2 并且您必须执行 5/2.0 才能获得浮点结果.在 Python 3 中，5/2 == 2.5 并且您必须执行 5//2 才能获得除法的地板整数结果.很有可能当你在你的 x 和 y 上操作时，你将它除以在 Python 2 中给你一个整数但在 Python 3 中给你的东西那个浮点数，所以当你尝试将它用作列表索引时...BOOM

In Python 2, 5/2 == 2 and you had to do 5/2.0 to get the floating point result. In Python 3, 5/2 == 2.5 and you have to do 5//2 to get the floored integer result of the division. Chances are whenever you're operating on your x and y, you're dividing it by something that in Python 2 gave you an integer but in Python 3 is leaving you with that floating point, so when you try to use it as a list index...BOOM

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