用C声明和初始化数组 [英] Declaring and initializing arrays in C

问题描述

有没有先申报，然后用C初始化数组？一个办法

到目前为止，我一直在初始化数组是这样的：

  INT myArray的[SIZE] = {1,2,3,4，...};
 

但我需要做这样的事情。

  INT myArray的[SIZE]myArray的= {1,2,3,4，...};
 

解决方案

在C99可以组合使用复合字面常量与的memcpy

做

 的memcpy（myarray中，（INT []）{1，2，3，4}，sizeof的myArray的）;
 

（假定源的尺寸和目标的大小是相同的）。

在C89 / 90，你可以模仿通过声明一个额外的源阵列

  const int的SOURCE [SIZE] = {1，2，3，4}; / *也许`static`？ * /
INT myArray的[SIZE]
...
的memcpy（myArray的，来源，sizeof的myArray的）;
 

Is there a way to declare first and then initialize an array in C?

So far I have been initializing an array like this:

int myArray[SIZE] = {1,2,3,4....};

But I need to do something like this

int myArray[SIZE];

myArray = {1,2,3,4....};

解决方案

In C99 you can do it using a compound literal in combination with memcpy

memcpy(myarray, (int[]) { 1, 2, 3, 4 }, sizeof myarray);

(assuming that the size of the source and the size of the target is the same).

In C89/90 you can emulate that by declaring an additional "source" array

const int SOURCE[SIZE] = { 1, 2, 3, 4 }; /* maybe `static`? */
int myArray[SIZE];
...
memcpy(myarray, SOURCE, sizeof myarray);

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