C中的字符数组声明和初始化 [英] Char array declaration and initialization in C

问题描述

我很好奇为什么在 C 中不允许这样做:

I was curious about why this is not allowed in C:

char myarray[4];

myarray = "abc";

这是允许的:

char myarray[4] = "abc";

我知道在第一种情况下我应该使用 strcpy:

I know that in the first case I should use strcpy:

char myarray[4];

strcpy(myarray, "abc");

但是为什么不允许声明和随后的初始化，而允许声明和同时初始化呢?和C程序的内存映射有关系吗?

But why declaration and later initialization is not allowed and declaration and simultaneous initialization is allowed? Does it relate to memory mapping of C programs?

谢谢！

推荐答案

那是因为你的第一个代码片段没有执行初始化，而是赋值:

That's because your first code snippet is not performing initialization, but assignment:

char myarray[4] = "abc";  // Initialization.

myarray = "abc";          // Assignment.

并且数组在 C 中不能直接赋值.

And arrays are not directly assignable in C.

myarray 这个名字实际上解析为它的第一个元素的地址(&myarray[0])，它不是一个左值，因此不能成为作业的目标.

The name myarray actually resolves to the address of its first element (&myarray[0]), which is not an lvalue, and as such cannot be the target of an assignment.

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