字符数组声明和初始化用C [英] Char array declaration and initialization in C

问题描述

我很好奇，为什么这不是在C允许的：

I was curious about why this is not allowed in C:

char myarray[4];

myarray = "abc";

这是允许的：

char myarray[4] = "abc";

我知道，在第一种情况下，我应该使用的strcpy

char myarray[4];

strcpy(myarray, "abc");

但为什么声明，后来初始化是不允许的，申报和同时初始化被允许？它与C程序的内存映射？

But why declaration and later initialization is not allowed and declaration and simultaneous initialization is allowed? Does it relate to memory mapping of C programs?

谢谢！

推荐答案

这是因为你的第一个code段未执行的初始化的，但是的分配的：

That's because your first code snippet is not performing initialization, but assignment:

char myarray[4] = "abc";  // Initialization.

myarray = "abc";          // Assignment.

和数组是不是在C直接分配。

And arrays are not directly assignable in C.

名称 myarray中其实解析为它的第一个元素的地址（＆放大器; myArray的[0] ），这是不是一个左值，因此不能作为赋值的目标。

The name myarray actually resolves to the address of its first element (&myarray[0]), which is not an lvalue, and as such cannot be the target of an assignment.

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