python用至少2个空格分割一个字符串 [英] python split a string with at least 2 whitespaces

问题描述

我只想在至少有两个或更多空格的地方拆分字符串.

I would like to split a string only where there are at least two or more whitespaces.

例如

str = '10DEUTSCH        GGS Neue Heide 25-27     Wahn-Heide   -1      -1'
print str.split()

结果:

['10DEUTSCH', 'GGS', 'Neue', 'Heide', '25-27', 'Wahn-Heide', '-1', '-1']

我希望它看起来像这样:

I would like it to look like this:

['10DEUTSCH', 'GGS Neue Heide 25-27', 'Wahn-Heide', '-1', '-1']

推荐答案

In [4]: import re    
In [5]: text = '10DEUTSCH        GGS Neue Heide 25-27     Wahn-Heide   -1      -1'
In [7]: re.split(r'\s{2,}', text)
Out[7]: ['10DEUTSCH', 'GGS Neue Heide 25-27', 'Wahn-Heide', '-1', '-1']

更新 2021+ 答案.

str.split 现在接受要拆分的正则表达式.

在此处阅读更多信息

Update 2021+ answer.

str.split now accepts regular expressions to split on.

read more here

row = '10DEUTSCH        GGS Neue Heide 25-27     Wahn-Heide   -1      -1'
df = pd.DataFrame({'string' : row},index=[0])

---

print(df)
                                              string
0  10DEUTSCH        GGS Neue Heide 25-27     Wahn...

---

df1 = df['string'].str.split('\s{2,}',expand=True)
print(df1)

           0                     1           2   3   4
0  10DEUTSCH  GGS Neue Heide 25-27  Wahn-Heide  -1  -1

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