如何在bash shell中将一个字符串拆分为由至少一个空格分隔的多个字符串? [英] How to split one string into multiple strings separated by at least one space in bash shell?

问题描述

我有一个包含许多单词的字符串，每两个单词之间至少有一个空格.如何将字符串拆分为单个单词以便循环遍历它们?

I have a string containing many words with at least one space between each two. How can I split the string into individual words so I can loop through them?

字符串作为参数传递.例如.${2} == "cat cat 文件".我怎样才能遍历它?

The string is passed as an argument. E.g. ${2} == "cat cat file". How can I loop through it?

另外，如何检查字符串是否包含空格?

Also, how can I check if a string contains spaces?

推荐答案

您是否尝试将字符串变量传递给 for 循环?例如，Bash 会自动在空白处拆分.

Did you try just passing the string variable to a for loop? Bash, for one, will split on whitespace automatically.

sentence="This is   a sentence."
for word in $sentence
do
    echo $word
done

 

This
is
a
sentence.

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