如何将一个字符串分割成由bash shell中至少有一个空格分隔多个字符串？ [英] How to split one string into multiple strings separated by at least one space in bash shell?

问题描述

我有一个字符串，就像一个句子，我知道肯定有很多的话至少有一个空间，每相邻的两个独立的。我怎么能分裂成单词串个人这样我就可以通过他们的循环？

I have a string, like a sentence, and I know for sure that there are many words with at least one space separate every adjacent two. How can I split the words into individual strings so I can loop through them?

---

编辑：
巴什
该字符串传递作为参数。例如$ {2}可能是猫，猫，文件。所以哪能通过这个ARG $循环{2}？

Bash The string is passed in as an argument. e.g. ${2} might be "cat '' cat '' file". so how can I loop through this arg ${2}?

---

另外，如何检查是否字符串包含空格？

Also, how to check if a string contains spaces?

推荐答案

你尝试只是路过字符串变量为为循环？击为一体，将自动分割的空白。

Did you try just passing the string variable to a for loop? Bash, for one, will split on whitespace automatically.

sentence="This is   a sentence."
for word in $sentence
do
    echo $word
done

＆NBSP;

This
is
a
sentence.

这篇关于如何将一个字符串分割成由bash shell中至少有一个空格分隔多个字符串？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！