PHP比较两个数组，并得到匹配的值没有区别 [英] PHP compare two arrays and get the matched values not the difference

问题描述

我想比较两个数组，并得到仅存在两个阵列上，但不幸的价值观，我无法找到使用权阵列功能...

我找到了和array_diff（）功能：的 http://php.net/manual/en/function.array-diff.php

但它的两个阵列的区别。

示例：

  $ ARRAY1 =阵列（** **阿尔法，欧米茄，** **布拉沃，** **查理，**三角洲* *，** foxfrot **）;
$ =数组2 array(\"**alpha**\",\"gamma\",\"**bravo**\",\"x-ray\",\"**charlie**\",\"**delta**\",\"halo\",\"eagle\",\"**foxfrot**\");
 

预期输出：

  $结果=阵列（** **阿尔法，** **布拉沃，** **查理，** **三角洲， ** foxfrot **）;
 

解决方案

简单，使用 array_intersect（） 来代替：

  $结果= array_intersect（$数组1，$数组2）;
 

I'm trying to compare two arrays and get only the values that exist on both arrays but, unfortunately, I can't find the right array function to use...

I found the array_diff() function: http://php.net/manual/en/function.array-diff.php

But it's for the difference of the both arrays.

Example:

$array1 = array("**alpha**","omega","**bravo**","**charlie**","**delta**","**foxfrot**");
$array2 = array("**alpha**","gamma","**bravo**","x-ray","**charlie**","**delta**","halo","eagle","**foxfrot**");

Expected Output:

$result = array("**alpha**","**bravo**","**charlie**","**delta**","**foxfrot**");

解决方案

Simple, use array_intersect() instead:

$result = array_intersect($array1, $array2);

这篇关于PHP比较两个数组，并得到匹配的值没有区别的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！