PHP比较两个数组并获得匹配值没有区别 [英] PHP compare two arrays and get the matched values not the difference

问题描述

我试图比较两个数组，只获得两个数组上存在的值，但不幸的是，我找不到正确的数组函数使用...

我发现 array_diff（）函数： http://php.net/manual/en/function.array-diff.php

但这是为了两个数组的区别。 / p>

示例：

  $ array1 =数组（** alpha **，omega，** bravo **，** charlie **，** delta **，** foxfrot **）; 
 $ array2 = array（** alpha **，gamma，** bravo **，x-ray，** charlie **，** delta ** ，halo，eagle，** foxfrot **）; 
  

预期输出：

  $ result = array（** alpha **，** bravo **，** charlie **，** delta ** ** foxfrot **）; 
  

解决方案

/www.php.net/manual/en/function.array-intersect.php> array_intersect（） ：

  $ result = array_intersect（$ array1，$ array2）; 
  

I'm trying to compare two arrays and get only the values that exist on both arrays but, unfortunately, I can't find the right array function to use...

I found the array_diff() function: http://php.net/manual/en/function.array-diff.php

But it's for the difference of the both arrays.

Example:

$array1 = array("**alpha**","omega","**bravo**","**charlie**","**delta**","**foxfrot**");
$array2 = array("**alpha**","gamma","**bravo**","x-ray","**charlie**","**delta**","halo","eagle","**foxfrot**");

Expected Output:

$result = array("**alpha**","**bravo**","**charlie**","**delta**","**foxfrot**");

解决方案

Simple, use array_intersect() instead:

$result = array_intersect($array1, $array2);

这篇关于PHP比较两个数组并获得匹配值没有区别的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！