比较两个数组并获得常用项 [英] compare two arrays and get the common items

问题描述

我有两个数组，但它们有不同的长度。我想比较这两个数组和将常用项目放到新数组。同时不应该有重复项是第三个数组。
我真的搞砸了这个，请给我一个帮助。
非常感谢。 。 。

I have two arrays, but they have different lengths. I want to compare these two arrays and put common items to a new array. meanwhile there should not be have duplicate items is the third array. I really mess up with this, please give me a help. highly thankful . . .

推荐答案

这样的事情？

NSMutableSet* set1 = [NSMutableSet setWithArray:array1];
NSMutableSet* set2 = [NSMutableSet setWithArray:array2];
[set1 intersectSet:set2]; //this will give you only the obejcts that are in both sets

NSArray* result = [set1 allObjects];

这样做的好处是不会查找数组中的对象，同时循环遍历另一个数组，具有N ^ 2的复杂性，如果数组很大，可能需要一段时间。

This has the benefit of not looking up the objects in the array, while looping through another array, which has N^2 complexity and may take a while if the arrays are large.

编辑：set2不必是可变的，也可以只使用

set2 doesn't have to be mutable, might as well use just

NSSet* set2 = [NSSet setWithArray:array2];

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