如何申报C ++字符串数组？ [英] How to declare an array of strings in C++?

问题描述

我想遍历字符串中尽可能最好的方式静态数组中的所有元素。我希望能够宣布它在同一行，并轻松地添加/移除它的元素，而无需跟踪号码。听起来很简单，不是吗？

I am trying to iterate over all the elements of a static array of strings in the best possible way. I want to be able to declare it on one line and easily add/remove elements from it without having to keep track of the number. Sounds really simple, doesn't it?

可能不解决方案：

vector<string> v;
v.push_back("abc");
b.push_back("xyz");

for(int i = 0; i < v.size(); i++)
    cout << v[i] << endl;

问题 - 没办法用字符串列表

Problems - no way to create the vector on one line with a list of strings

可能无解2：

string list[] = {"abc", "xyz"};

问题 - 没有办法自动获得字符串的数量（据我所知）

Problems - no way to get the number of strings automatically (that I know of).

有必须这样做的一个简单的方法。

There must be an easy way of doing this.

推荐答案

借助提高好像是你在寻找什么分配库。它使集装箱分配常数比以往更容易。

The boost assign library seems to be exactly what you are looking for. It makes assigning constants to containers easier than ever.

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