检查一个变量是迭代? [英] Check if a variable is iterable?

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问题描述

有没有什么办法来检查,如果一个任意变量类型是可迭代?

Is there any way to check if an arbitrary variable type is iterable?

所以要检查它是否索引元素或其实我可以遍历它的孩子吗? (例如使用的foreach?)

So to check if it has indexed elements or I can actually loop over it's children? (Use foreach for example?)

是否有可能创建一个通用模板?

Is it possible to create a universal template for that?

我已经找到了其他编程语言技术,同时寻找它。但仍然必须找出如何做到这一点的C ++。

I've found techniques for other programming languages while searching for it. Yet still have to find out how to do this in C++.

推荐答案

这取决于你所说的迭代是什么。这是C ++中的松散的概念,因为你可以在许多不同的方式实现迭代器。

It depends on what you mean by "iterable". It is a loose concept in C++ since you could implement iterators in many different ways.

如果按的foreach 你指的是C ++ 11的射程为基础的for循环,类型的需求开始()定义和端()方法,并返回到运营商应对迭代器!=
符++ 运算符*

If by foreach you're referring to C++11's range-based for loops, the type needs begin() and end() methods to be defined and to return iterators that respond to operator!=, operator++ and operator*.

如果你的意思是Boost的BOOST_FOREACH帮手,后来看到 BOOST_FOREACH扩展

If you mean Boost's BOOST_FOREACH helper, then see BOOST_FOREACH Extensibility.

如果你的设计,你有一个共同的接口,所有的迭代容器继承,那么你可以使用C ++ 11的的的std :: is_bas​​e_of

If in your design you have a common interface that all iterable containers inherit from, then you could use C++11's std::is_base_of:

struct A : IterableInterface {}
struct B {}
template <typename T>
constexpr bool is_iterable() {
    return std::is_base_of<IterableInterface, T>::value;
}
is_iterable<A>(); // true
is_iterable<B>(); // false

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