如何字符的3D数组传递给函数 [英] How to pass 3D array of chars to a function

问题描述

我有字符表[] [] []的三维数组，我想将它传递给一个void函数，因此它可以进行更改。我怎样才能做到这一点？

 无效化妆（字符轻微[] [] []）;.....
烧焦更大[20] [30] [50];
使（较大）;
 

我想这是不是要去工作。

编辑：与此连接的另一个问题是：说我想要做一个复制功能将一个字符串复制到阵列 - 我应该怎么称呼在功能上的strcpy

？

 无效复印件（CHAR（*未成年人）[] []）{CHAR米[50] =asdasdasd;
的strcpy（次要[] []，M）;
}
 

解决方案

如果你想传递的阵列的，就像那一个，而不是一个你动态地<$ C分配$ C>的malloc （这将是指针的几级，不是真正的数组），任何下列函数原型将工作：

• 无效化妆（字符未成年人[20] [30] [50]）


• 无效化妆（字符轻微[] [30] [50]）


• 无效化妆（CHAR（*未成年人）[30] [50]）

的原因是你不能拥有像无效化妆（CHAR ***未成年人）是因为轻微只会衰变成一个指针数组的数组，它不会腐烂不止一次这么多说了。

I have a 3D array of chars table[][][] and I want to pass it to a void function so it can make changes to it. How can I do this?

void make(char minor[][][]);

.....
char greater[20][30][50];
make(greater);

I guess this is not gonna work.

EDIT: Another question connected with this: Say I want to make a copy function to copy a string into the array - how should I call the strcpy in the function?

void copy(char (*minor)[][])

{ char m[50] = "asdasdasd"; 
strcpy(minor[][],m);
}

解决方案

If you wanted to pass an array, just like that one, as opposed to one you've dynamically allocated with malloc (which would be a few levels of pointers, not real arrays), any of the below function prototypes will work:

• void make(char minor[20][30][50])
• void make(char minor[][30][50])
• void make(char (*minor)[30][50])

The reason being you can't have something like void make(char ***minor) is because minor will only decay into a pointer to an array of arrays, it won't decay more than once so to say.

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