如何捕获多个重复的组? [英] How to capture multiple repeated groups?

问题描述

我需要捕获多个相同模式的组.假设，我有以下字符串:

I need to capture multiple groups of the same pattern. Suppose, I have the following string:

HELLO,THERE,WORLD

我写了以下模式

^(?:([A-Z]+),?)+$

我想要它做的是捕获每个单词，以便第 1 组是:HELLO"，第 2 组是THERE"；并且第3组是世界".我的正则表达式实际捕获的只是最后一个，即WORLD".

What I want it to do is to capture every single word, so that Group 1 is : "HELLO", Group 2 is "THERE" and Group 3 is "WORLD". What my regex is actually capturing is only the last one, which is "WORLD".

我正在测试我的正则表达式 here 我想将它与 Swift 一起使用(也许 Swift 中有一种方法以某种方式获得中间结果，以便我可以使用它们?)

I'm testing my regular expression here and I want to use it with Swift (maybe there's a way in Swift to get intermediate results somehow, so that I can use them?)

更新:我不想使用split.我现在只需要知道如何捕获与模式匹配的所有组，而不仅仅是最后一个.

UPDATE: I don't want to use split. I just need to now how to capture all the groups that match the pattern, not only the last one.

推荐答案

在模式中有一个组，您只能在该组中获得一个确切的结果.如果您的捕获组被模式重复(您在周围的非捕获组上使用了 + 量词)，则只会存储与它匹配的最后一个值.

With one group in the pattern, you can only get one exact result in that group. If your capture group gets repeated by the pattern (you used the + quantifier on the surrounding non-capturing group), only the last value that matches it gets stored.

您必须使用您的语言的正则表达式实现函数来查找模式的所有匹配，然后您必须删除非捕获组的锚点和量词(并且您可以省略非捕获组本身也是如此).

You have to use your language's regex implementation functions to find all matches of a pattern, then you would have to remove the anchors and the quantifier of the non-capturing group (and you could omit the non-capturing group itself as well).

或者，扩展您的正则表达式，让模式包含您想要在结果中获得的每个组一个捕获组:

Alternatively, expand your regex and let the pattern contain one capturing group per group you want to get in the result:

^([A-Z]+),([A-Z]+),([A-Z]+)$

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