正则表达式匹配偶数个字母 [英] Regex match even number of letters

问题描述

我需要将 Python 中的表达式与仅匹配偶数个字母出现的正则表达式进行匹配.例如:

<前>AAA # 不匹配AA#匹配fsfaAAasdf # 匹配sAfA # 匹配sdAAewAsA # 匹配AeAiA # 不匹配

偶数个 As SHOULD 匹配.

解决方案

试试这个正则表达式:

^[^A]*((AA)+[^A]*)*$

如果 A 不需要连续:

^[^A]*(A[^A]*A[^A]*)*$

I need to match an expression in Python with regular expressions that only matches even number of letter occurrences. For example:

AAA        # no match
AA         # match
fsfaAAasdf # match
sAfA       # match
sdAAewAsA  # match
AeAiA      # no match

An even number of As SHOULD match.

解决方案

Try this regular expression:

^[^A]*((AA)+[^A]*)*$

And if the As don’t need to be consecutive:

^[^A]*(A[^A]*A[^A]*)*$

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