可以使 [a-zA-Z] Python 正则表达式模式匹配和替换非 ASCII Unicode 字符吗? [英] Can the [a-zA-Z] Python regex pattern be made to match and replace non-ASCII Unicode characters?
问题描述
在下面的正则表达式中,我希望字符串中的每个字符都替换为X",但它不起作用.
在 Python 2.7 中:
<预><代码>>>>进口重新>>>re.sub(u"[a-zA-Z]","X","dfäg")'XX\xc3\xa4X'或
<预><代码>>>>re.sub("[a-zA-Z]","X","dfäg",re.UNICODE)你'XX\xe4X'在 Python 3.4 中:
<预><代码>>>>re.sub("[a-zA-Z]","X","dfäg")'XXäX'是否有可能以某种方式配置"[a-zA-Z] 模式以匹配ä"、ü"等?如果无法做到这一点,我如何在方括号之间创建一个类似的字符范围模式,其中包括通常的完整字母表"范围内的 Unicode 字符?我的意思是,在像德语这样的语言中,'ä' 将被放置在字母表中靠近 'a' 的某个位置,因此人们会期望它包含在 'a-z' 范围内.
您可以使用
(?![\d_])\w
带有 Unicode 修饰符.(?![\d_])
前瞻限制了 \w
速记类,因为它不能匹配任何数字 (\d
>) 或下划线.
参见正则表达式演示
导入重新打印 (re.sub(r"(?![\d_])\w","X","dfäg"))# =>XXX
至于 Python 2:
# -*- 编码:utf-8 -*-进口重新s = "dfäg"w = re.sub(ur'(?![\d_])\w', u'X', s.decode('utf8'), 0, re.UNICODE).encode("utf8")打印(宽)
In the following regular expression, I would like each character in the string replaced with an 'X', but it isn't working.
In Python 2.7:
>>> import re
>>> re.sub(u"[a-zA-Z]","X","dfäg")
'XX\xc3\xa4X'
or
>>> re.sub("[a-zA-Z]","X","dfäg",re.UNICODE)
u'XX\xe4X'
In Python 3.4:
>>> re.sub("[a-zA-Z]","X","dfäg")
'XXäX'
Is it possible to somehow 'configure' the [a-zA-Z] pattern to match 'ä', 'ü', etc.? If this can't be done, how can I create a similar character range pattern between square brackets that would include Unicode characters in the usual 'full alphabet' range? I mean, in a language like German, for instance, 'ä' would be placed somewhere close to 'a' in the alphabet, so one would expect it to be included in the 'a-z' range.
You may use
(?![\d_])\w
With the Unicode modifier. The (?![\d_])
look-ahead is restricting the \w
shorthand class so as it could not match any digits (\d
) or underscores.
See regex demo
import re
print (re.sub(r"(?![\d_])\w","X","dfäg"))
# => XXXX
As for Python 2:
# -*- coding: utf-8 -*-
import re
s = "dfäg"
w = re.sub(ur'(?![\d_])\w', u'X', s.decode('utf8'), 0, re.UNICODE).encode("utf8")
print(w)
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