如何将带引号的字符串与其中的转义引号匹配? [英] How to match a quoted string with escaped quotes in it?

问题描述

/^"((?:[^"]|\\.)*)"/

针对这个字符串:

"quote\_with\\escaped\"characters" more

它只匹配到 \"，虽然我已经明确地将 \ 定义为转义字符(并且它匹配 \_ 和\\ 很好...).

It only matches until the \", although I've clearly defined \ as an escape character (and it matches \_ and \\ fine...).

推荐答案

如果您颠倒两个选项的顺序，它可以正常工作:

It works correctly if you flip the order of your two alternatives:

/^"((?:\\.|[^"])*)"/

问题是，否则重要的 \ 字符会在 before 尝试匹配 \" 之前被吃掉.它之前对 有效\\ 和 \_ 只是因为任一对中的两个字符都与您的 [^"] 匹配.

The problem is that otherwise the important \ character gets eaten up before it tries matching \". It worked before for \\ and \_ only because both characters in either pair get matched by your [^"].

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