正则表达式用两边的空格替换给定的单词或根本不替换 [英] regex to replace a given word with space at either side or not at all

问题描述

我正在使用 PHP 中的一些代码从搜索引擎中获取引用数据，为我提供用户输入的查询.

I am working with some code in PHP that grabs the referrer data from a search engine, giving me the query that the user entered.

然后我想从该字符串中删除某些停用词(如果存在).但是，单词的两端可能有也可能没有空格.

I would then like to remove certain stop words from that string if they exist. However, the word may or may not have a space at either end.

比如我一直用str_replace删除一个词如下:

For example, I have been using str_replace to remove a word as follows:

$keywords = str_replace("for", "", $keywords);
$keywords = str_replace("sale", "", $keywords);

但如果 $keywords 值是婴儿配方"，它会将其更改为婴儿穆拉" - 删除for"部分.

but if the $keywords value is "baby formula" it will change it to "baby mula" - removing the "for" part.

无需为for"和for"创建进一步的 str_replace 帐户 - 是否有我可以使用的 preg_replace 类型命令来删除给定的单词，如果它的两端有空格?

Without having to create further str_replace's that account for " for" and "for " - is there a preg_replace type command I could use that would remove the given word if it is found with a space at either end?

我的想法是将所有停用词放入一个数组中并以这种方式单步执行，我怀疑 preg_replace 将比单步执行多个 str_replace 行更快.

My idea would be to put all of the stop words into an array and step through them that way and I suspect that a preg_replace is going to be quicker than stepping through multiple str_replace lines.

更新:感谢你们使用以下组合解决了:

UPDATE: Solved thanks to you guys using the following combination:

$keywords = "...";
$stopwords = array("for","each");
foreach($stopwords as $stopWord)
{
    $keywords = preg_replace("/(\b)$stopWord(\b)/", "", $keywords);   
}

推荐答案

$keywords = "...";
$stopWords = array("for","sale");
foreach($stopWords as $stopWord){
    $keywords = preg_replace("/(\b)$stopWord(\b)/", "", $keywords);
}

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