如何提取“零件"根据某些 RegExp 模式的字符串? [英] How to extract "parts" of a String according to some RegExp pattern?

问题描述

在 JavaScript 中，给定一个正则表达式模式和一个字符串:

In JavaScript, given a regexp pattern and a string:

var pattern = '/this/[0-9a-zA-Z]+/that/[0-9a-zA-Z]+';
var str = '/this/12/that/34';

如何返回包含以下内容的数组:

How to return an array containing:

['12', '34']

以下匹配整个输入字符串，从而将其作为一个整体返回.

The following matches the whole input string and thus returns it as a whole.

var res1 = '/this/12/that/34'.match(/\/this\/[0-9a-zA-Z]+\/that\/[0-9a-zA-Z]+/));

以下匹配输入字符串的所有部分".

The following matches all "parts" of the input string.

var res2 = '/this/12/that/34'.match(/[0-9a-zA-Z]+/g));

推荐答案

使用捕获组:

var res1 = '/this/12/that/34'.match(/\/this\/([0-9a-zA-Z]+)\/that\/([0-9a-zA-Z]+)/);

你会得到一个包含 3 个元素的数组:

You will get an array containing 3 elements:

1. 整场比赛；

1. The whole match;

12

34

并且您可以使用 .slice(1) 删除第一个元素:

And you can use .slice(1) to remove the first element:

var res1 = '/this/12/that/34'.match(/\/this\/([0-9a-zA-Z]+)\/that\/([0-9a-zA-Z]+)/).slice(1);

这篇关于如何提取“零件"根据某些 RegExp 模式的字符串?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！