C# 获取引用程序集中的相对路径 [英] C# Get relative path in referenced assembly

问题描述

我有 2 个项目 Project A , Project B ,项目 A 引用了项目 B ，项目 A 是一个可执行文件.

I have 2 projects Project A , Project B , project A has a reference to project B , project A is an executable.

  Project A --> Project B 

在项目 B 中有一个名为MyFolder"的目录

inside project B there is a directory called "MyFolder"

所以灵魂层次如下:

    MySolution 
       -  A
       -  B 
          - MyFolder 

如何从项目 A(可执行文件)中获取 MyFolder 的相对路径.

how do i get a Relative Path to MyFolder from with in project A(Executable).

我找到了很多答案，说明如下:

I found allot of answer which state the following :

  sring path = Assembly.GetAssembly(typeof(SomeClassInBProject)).Location;

我从这里返回的路径是 A 的 bin\debug 中 B.dll 的路径，我如何检索该 .dll 中的路径.

The path i got back from this is the path to B.dll in A's bin\debug ,how can i retrieve a path with in that .dll .

我也试过:

        Assembly assembly = Assembly.GetAssembly(typeof(SomeClassInBProject));
        FileStream fs = assembly.GetFile(@"MyFolder\myFile"); 

        and 

         FileStream fs = assembly.GetFile("MyFolder\myFile");  

        and 

         FileStream fs = assembly.GetFile("myFile");  

fs i 始终为空.

推荐答案

Is Uri.MakeRelativeUri 你在找什么?

string pathA = Assembly.GetExecutingAssembly().Location;
string pathB = Assembly.GetAssembly(typeof(SomeClassInBProject)).Location;

Uri pathAUri = new Uri(pathA);
Uri pathBUri = new Uri(pathB);

string relativePath = pathAUri.MakeRelativeUri(pathBUri).OriginalString;
string relativeMyFolder = Path.Combine(relativePath, "MyFolder");

更新

您可以使用 Assembly.GetFile() 方法返回一个 FileStream.FileStream 有一个 Name 属性，你可以在上面的代码中使用.

You can use the Assembly.GetFile() method which returns a FileStream. FileStream has a Name property you could use in the code above.

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