字符数组后,性格怪异 [英] Strange character after an array of characters
问题描述
我是一个真正的初学者到C,但我学习!
I am a real beginner to C, but I am learning!
我已经在这个问题之前绊倒,并决定要求它的原因是什么。并请说明您的答案,所以我可以学习的。
I've stumbled upon this problem before and decided to ask what the reason for it is. And please explain your answers so I can learn.
我做了一个程序,它允许你输入5个字符,然后告诉你写的字也回复他们,例如:asdfg - gfdsa。
奇怪的是,一个奇怪的字符被输入的原字后显示。
I have made a program which allows you to input 5 characters and then show the characters you wrote and also revert them, example: "asdfg" - "gfdsa". The weird thing is that a weird character is shown after the original characters that was inputted.
下面是code:
char str[5];
char outcome[] = "OOOOO";
int i;
int u;
printf("Enter five characters\n");
scanf("%s", str);
for(i = 4, u = 0; i >=0; u++, i--){
outcome[i] = str[u];
}
printf("\nYou wrote: %s. The outcome is: %s.", str , outcome);
return 0;
如果我输入:asdfg它显示:asdfg♣,这是为什么
If I enter: "asdfg" it shows: "asdfg♣", why is that?
感谢您的时间和请说明您的答案:)
Thank you for your time and please explain your answers :)
推荐答案
由于没有空终止符。在C字符串是连续字节(字符)序列与定点字符到底叫空终止('\\ 0'
)。您code获取用户输入并填充所有5个字符,所以没有结束到您的字符串。然后,当你打印字符串将打印5个字符(asdfg
),它会继续打印任何垃圾是在堆栈上,直到遇到一个空终止符。
Because there's no null terminator. In C a "string" is a sequence of continuous bytes (chars) that end with a sentinel character called a null terminator ('\0'
). Your code takes the input from the user and fills all 5 characters, so there's no "end" to your string. Then when you print the string it will print your 5 characters ("asdfg"
) and it will continue to print whatever garbage is on the stack until it hits a null terminator.
char str[6] = {'\0'}; //5 + 1 for '\0', initialize it to an empty string
...
printf("Enter five characters\n");
scanf("%5s", str); // limit the input to 5 characters
有关限制格式specificer的好处是,即使输入大于5个字符长,只有5将被存储到您的字符串,总是留有余地的空终止符。
The nice thing about the limit format specificer is that even if the input is longer than 5 characters, only 5 will be stored into your string, always leaving room for that null terminator.
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