性格整数用C [英] Character to Integer in C
本文介绍了性格整数用C的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有没有办法为一个字符转换为C中的整数?
Is there a way to convert a character to an integer in C?
例如,
'5' - > 5
for example, '5' -> 5
感谢。
推荐答案
按照对方回复,这是罚款:
As per other replies, this is fine:
char c = '5';
int x = c - '0';
此外,对于错误检查,你不妨检查一下ISDIGIT(c)是真正的第一。请注意,你不能完全可移植做字母相同的,例如:
Also, for error checking, you may wish to check isdigit(c) is true first. Note that you cannot completely portably do the same for letters, for example:
char c = 'b';
int x = c - 'a'; // x is now not necessarily 1
该标准保证了数字'0'到'9'的char值是连续的,但使得其他字符不能保证像英文字母。
The standard guarantees that the char values for the digits '0' to '9' are contiguous, but makes no guarantees for other characters like letters of the alphabet.
这篇关于性格整数用C的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文