如何显示单个列表?Ruby on Rails [英] how to display individual listings? Ruby on Rails

问题描述

我目前正在一个简单的网站上工作，人们可以在其中列出帖子.大部分代码基于 Michael Hartl 的教程.我希望用户能够单击单独显示列表的链接.目前，每个用户的列表都可以在

下找到

http://localhost:3000/users/id

每个列表都有自己的 ID这是我的路线

Rails.application.routes.draw 做资源:用户资源:会话，仅:[:new, :create, :destroy]资源:列表根'static_pages#home'匹配'/signup'，到:'users#new'，通过:'get'匹配'/signin'，到:'sessions#new'，通过:'get'匹配 '/signout'，到:'sessions#destroy'，通过:'delete'匹配'/help'，到:'static_pages#help'，通过:'get'匹配'/contact'，到:'static_pages#contact'，通过:'get'匹配'/about'，到:'static_pages#about'，通过:'get'匹配'/new'，到:'listings#new'，通过:'get'

这是我的listing_controller.rb

class ListingsController <应用控制器before_action :signed_in_user, only: [:create, :destroy, :edit]before_action :correct_user, only: :destroy定义创建@listing = current_user.listings.build(listing_params)如果@listing.saveflash[:success] = "职位发布已创建"重定向到当前用户别的呈现列表/新"结尾结尾定义编辑结尾高清秀@listing = Listing.find(params[:id])结尾定义新@listing = Listing.new@listings = Listing.paginate(page: params[:page])结尾销毁@listing.destroy重定向到当前用户结尾私人的定义列表参数params.require(:listing).permit(:description, :location, :title)结尾定义正确_用户@listing = current_user.listings.find_by(id: params[:id])如果@listing.nil，则重定向到current_user?结尾def current_listing@listings = listing.find(params[:id])结尾结尾

我还在列表列表文件夹下为每个列表创建了一个显示页面.显示页面本身有效.这是清单的 show.html.erb

<div class="col-md-6"><div class="col-md-6"><h3><%=@listing.title%></h3><h3><%=@listing.location %></h3><p><%=@listing.description%></p><br><div class="center"><%= link_to "Apply Now", '#', class: "btn btn-info", data: {no_turbolink: true} %>

<div class="show_link_position"><% if current_user == @listing.user %><%= link_to 'Edit', '#', class: "btn btn-link" %>|<%结束%><%= link_to 'Back', current_user, class: "btn btn-link" %>

现在我想在用户页面(在每个列表下)有一个链接，可以单独链接到每个帖子.

我正在寻找这样的东西如何显示单个微博的链接?(ruby on rails 3)

谢谢如果您需要更多信息，请告诉我

解决方案

这是我为使其工作所做的工作(借助以下 stackoverflow 帖子如何显示指向单个微博的链接?(ruby on rails 3))

路线 rb.

匹配 '/users/:id/:id', 到 'listings#show', via: :get, as: :user_listing

用户查看文件

添加链接

<%= link_to "Show", user_listing_path(id: @user.id, id: listing.id) %></li>

更改了我的列表控制器文件

def 显示@user = User.find_by_id(params[:id])@listing = Listing.find_by_id(params[:id])结尾

I am currently working on a simple website where people can list postings. Most of the code is based on Michael Hartl's tutorial. I want users to have the ability to click on a link that displays the listing individually. currently, the listings' of each user are found under

http://localhost:3000/users/id

Every listing has it's own id Here are my routes

Rails.application.routes.draw do
    resources :users
    resources :sessions, only: [:new, :create, :destroy]
    resources :listings


  root 'static_pages#home'


  match '/signup',  to: 'users#new',            via: 'get'
  match '/signin',   to: 'sessions#new',          via: 'get'
  match '/signout', to: 'sessions#destroy',     via:'delete'
  match '/help',      to: 'static_pages#help',    via: 'get'
  match '/contact',   to: 'static_pages#contact',  via: 'get'
  match '/about',     to: 'static_pages#about',   via: 'get' 
  match '/new',     to: 'listings#new',           via: 'get' 

Here is my listing_controller.rb

class ListingsController < ApplicationController
    before_action :signed_in_user, only: [:create, :destroy, :edit]
    before_action :correct_user,   only: :destroy

def create
    @listing = current_user.listings.build(listing_params)
    if @listing.save
        flash[:success] = "Job Post created"
        redirect_to current_user
        else
            render 'listings/new'
        end
    end

    def edit
    end

    def show
        @listing = Listing.find(params[:id])

    end

    def new
        @listing = Listing.new
        @listings = Listing.paginate(page: params[:page])
    end

def destroy 
    @listing.destroy
    redirect_to current_user
end

private 

def listing_params
    params.require(:listing).permit(:description, :location, :title)
end

def correct_user
    @listing = current_user.listings.find_by(id: params[:id])
    redirect_to current_user if @listing.nil?
end

def current_listing
    @listings = listing.find(params[:id])
end

end

I also created a show page for each listing under listings the listings folder. The show page itself works. Here is the show.html.erb for the listing

<div class="show_listing">

    <div class="col-md-6">
    <div class="col-md-6">
        <h3><%= @listing.title %></h3>
        <h3><%= @listing.location %></h3>
        <p><%= @listing.description %></p><br>
        <div class="center">
        <%= link_to "Apply Now", '#', class: "btn btn-info", data: {no_turbolink: true} %>
    </div>
    </div>
</div>
</div>

<div class="show_link_position">
<% if current_user == @listing.user %>
<%= link_to 'Edit', '#', class: "btn btn-link" %> |
<% end %>
<%= link_to 'Back', current_user, class: "btn btn-link" %>
</div>

Now I would like to have a link on the user page (under each listing) that would link to each post individually.

I'm looking for something like this how to display a link to individual microposts? (ruby on rails 3)

Thank you Let me know if you need more information

解决方案

Here is what I did to get it to work (with the help of the following stackoverflow post how to display a link to individual microposts? (ruby on rails 3))

Routes rb.

match '/users/:id/:id', to 'listings#show', via: :get, as: :user_listing

users view file

add the link

<li><%= link_to "Show", user_listing_path(id: @user.id, id: listing.id) %></li>

Changed my listing_controller file

def show
            @user = User.find_by_id(params[:id])
            @listing = Listing.find_by_id(params[:id])

        end

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