我怎样才能像解压经典元组一样解压元组结构? [英] How can I unpack a tuple struct like I would a classic tuple?

问题描述

我可以像这样解压一个经典的元组:

I can unpack a classic tuple like this:

let pair = (1, true);
let (one, two) = pair;

如果我有一个元组结构，例如 struct Matrix(f32, f32, f32, f32) 并且我尝试解压缩它，我会收到关于意外类型"的错误:

If I have a tuple struct such as struct Matrix(f32, f32, f32, f32) and I try to unpack it, I get an error about "unexpected type":

struct Matrix(f32, f32, f32, f32);
let mat = Matrix(1.1, 1.2, 2.1, 2.2);
let (one, two, three, four) = mat;

导致此错误:

error[E0308]: mismatched types
  --> src/main.rs:47:9
   |
47 |     let (one, two, three, four) = mat;
   |
   = note: expected type `Matrix`
              found type `(_, _, _, _)`

如何解包元组结构?我是否需要将其显式转换为元组类型?还是我需要对其进行硬编码?

How can I unpack a tuple struct? Do I need to convert it explicitly to a tuple type? Or do I need to hardcode it?

推荐答案

很简单:只需添加类型名称即可！

struct Matrix(f32, f32, f32, f32);

let mat = Matrix(1.1, 1.2, 2.1, 2.2);
let Matrix(one, two, three, four) = mat;
//  ^^^^^^

这按预期工作.

它与普通结构完全一样.在这里，您可以绑定到字段名称或自定义名称(如 height):

It works exactly the same with normal structs. Here, you can bind either to the field name or a custom name (like height):

struct Point {
    x: f64,
    y: f64,
}

let p = Point { x: 0.0, y: 5.0 };
let Point { x, y: height } = p;

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