如何在函数调用中解压多个元组 [英] How to unpack multiple tuples in function call

问题描述

如果我有一个函数 def f(a, b, c, d) 和两个元组，每个元组有两个元素，有没有办法解压这些元组，以便我可以发送它们的值到函数?

f(*tup1, *tup2)

解决方案

截至 thePython 3.5.0 发布，PEP 448附加解包概括" 为这个有效的 Python 生成自然语法:

<预><代码>>>>f(*tup1, *tup2)1 2 2 3

在旧版本的 Python 中，您可能需要将元组连接在一起以提供单个扩展参数:

<预><代码>>>>tup1 = 1, 2>>>tup2 = 2, 3>>>定义 f(a, b, c, d):打印(a，b，c，d)>>>f(*tup1+tup2)1 2 2 3

If I have a function def f(a, b, c, d) and two tuples, each with two elements, is there any way to unpack these tuples so that I can send their values to the function?

f(*tup1, *tup2)

解决方案

As of the release of Python 3.5.0, PEP 448 "Additional Unpacking Generalizations" makes the natural syntax for this valid Python:

>>> f(*tup1, *tup2)
1 2 2 3

In older versions of Python, you can need to concatenate the tuples together to provide a single expanded argument:

>>> tup1 = 1, 2
>>> tup2 = 2, 3
>>> def f(a, b, c, d):
        print(a, b, c, d)

>>> f(*tup1+tup2)
1 2 2 3

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