如何创建 UnsafeMutablePointer<CGPoint>快速对象 [英] How to create UnsafeMutablePointer<CGPoint> Object in swift

查看:60
本文介绍了如何创建 UnsafeMutablePointer<CGPoint>快速对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要调用 UIScrollViewDelegate 方法我不知道如何创建 UnsafeMutablePointer 对象.

I need to call the UIScrollViewDelegate methods I don't know how to create UnsafeMutablePointer object.

let pointer:UnsafeMutablePointer<CGPoint>  = CGPoint(x: 0, y: 1) as! UnsafeMutablePointer<CGPoint>

self.scrollViewWillEndDragging(self.collectionView, withVelocity: CGPoint(x: 0, y: 1), targetContentOffset: pointer)

func scrollViewWillEndDragging(scrollView: UIScrollView, withVelocity velocity: CGPoint, targetContentOffset: UnsafeMutablePointer<CGPoint>) 
{  
     //Some code here
}

推荐答案

import Foundation
var point = CGPoint(x: 10.0, y: 20.0)
let p = withUnsafeMutablePointer(&point) { (p) -> UnsafeMutablePointer<CGPoint> in
    return p
}

print(p.memory.x, p.memory.y) // 10.0 20.0
point.x = 100.0
print(p.memory.x, p.memory.y) // 100.0 20.0

借助 Swift 的语法糖

with help of Swift's syntactic sugar

import Foundation
var point = CGPoint(x: 10.0, y: 20.0)
let p = withUnsafeMutablePointer(&point) { $0 }

print(p.dynamicType) // UnsafeMutablePointer<CGPoint>

这篇关于如何创建 UnsafeMutablePointer&lt;CGPoint&gt;快速对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
相关文章
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆