iOS：转换UnsafeMutablePointer< Int8>在swift中串起来？ [英] iOS: Convert UnsafeMutablePointer<Int8> to String in swift?

问题描述

正如标题所说，在swift中将UnsafeMutablePointer转换为String的正确方法是什么？

As the title says, what is the correct way to convert UnsafeMutablePointer to String in swift?

//lets say x = UnsafeMutablePointer<Int8> 

var str = x.memory.????

我尝试使用x.memory.description显然它错了，给我一个错误的字符串值。

I tried using x.memory.description obviously it is wrong, giving me a wrong string value.

推荐答案

如果指针指向以NUL结尾的UTF-8字节的C字符串，则可以执行以下操作：

If the pointer points to a NUL-terminated C string of UTF-8 bytes, you can do this:

import Foundation

let x: UnsafeMutablePointer<Int8> = ...
// or UnsafePointer<Int8>
// or UnsafePointer<UInt8>
// or UnsafeMutablePointer<UInt8>

let str = String(cString: x)

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