UnsafeMutablePointer<Int8>来自 Swift 中的字符串 [英] UnsafeMutablePointer<Int8> from String in Swift

问题描述

我正在使用 Accelerate 框架中 LAPACK 实现中的 dgeev 算法来计算矩阵的特征向量和特征值.遗憾的是，Apple 文档中没有描述 LAPACK 功能，仅链接到 .

I'm using the dgeev algorithm from the LAPACK implementation in the Accelerate framework to calculate eigenvectors and eigenvalues of a matrix. Sadly the LAPACK functions are not described in the Apple Documentation with a mere link to http://netlib.org/lapack/faq.html included.

If you look it up, you will find that the first two arguments in dgeev are characters signifying whether to calculate eigenvectors or not. In Swift, it is asking for UnsafeMutablePointer<Int8>. When I simply use "N", I get an error. The dgeev function and the error are described in the following screenshot

What should I do to solve this?

解决方案

The "problem" is that the first two parameters are declared as char * and not as const char *, even if the strings are not modified by the function:

int dgeev_(char *__jobvl, char *__jobvr, ...);

is mapped to Swift as

func dgeev_(__jobvl: UnsafeMutablePointer<Int8>, __jobvr: UnsafeMutablePointer<Int8>, ...) -> Int32;

A possible workaround is

let result = "N".withCString { 
    dgeev_(UnsafeMutablePointer($0), UnsafeMutablePointer($0), &N, ...)
}

Inside the block, $0 is a pointer to a NUL-terminated array of char with the UTF-8 representation of the string.

---

Remark: dgeev_() does not modify the strings pointed to by the first two arguments, so it "should be" declared as

int dgeev_(const char *__jobvl, const char *__jobvr, ...);

which would be mapped to Swift as

func dgeev_(__jobvl: UnsafePointer<Int8>, __jobvr: UnsafePointer<Int8>, ...) -> Int32;

and in that case you could simply call it as

let result = dgeev_("N", "N", &N, ...)

because Swift strings are converted to UnsafePointer<Int8>) automatically, as explained in String value to UnsafePointer<UInt8> function parameter behavior.

这篇关于UnsafeMutablePointer&lt;Int8&gt;来自 Swift 中的字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！